Javascript Url Remove All Query Params Except

const urlObj = new URL('https://www.mydomain.com/test?x=1&y=2&z=3')// remove all query params except x and yconst keys = Array.from(urlObj.searchParams.keys())keys.forEach(key => {  if (!(['x', 'y'].includes(key))) {    urlObj.searchParams.delete(key)  }})  let url = urlObj.toString() // https://www.mydomain.com/test?x=1&y=2"